连CB,则∠ACB=90°=∠ADC∠绝竖好ACD=∠ABC∴ΔACD∽ΔABC∴AD:AC=AC:并铅纤源AV∴AB=5/2
标签:AB,直径
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连CB,则∠ACB=90°=∠ADC∠绝竖好ACD=∠ABC∴ΔACD∽ΔABC∴AD:AC=AC:并铅纤源AV∴AB=5/2
标签:AB,直径